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6x-12+4(x-7)=5(2x-4)-1
We move all terms to the left:
6x-12+4(x-7)-(5(2x-4)-1)=0
We multiply parentheses
6x+4x-(5(2x-4)-1)-28-12=0
We calculate terms in parentheses: -(5(2x-4)-1), so:We add all the numbers together, and all the variables
5(2x-4)-1
We multiply parentheses
10x-20-1
We add all the numbers together, and all the variables
10x-21
Back to the equation:
-(10x-21)
10x-(10x-21)-40=0
We get rid of parentheses
10x-10x+21-40=0
We add all the numbers together, and all the variables
-19!=0
There is no solution for this equation
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