6x-12+x=2(3x-10)

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Solution for 6x-12+x=2(3x-10) equation: 



6x-12+x=2(3x-10)

We move all terms to the left:

6x-12+x-(2(3x-10))=0

We add all the numbers together, and all the variables

7x-(2(3x-10))-12=0



We calculate terms in parentheses: -(2(3x-10)), so:

2(3x-10)

We multiply parentheses

6x-20

Back to the equation:

-(6x-20)



We get rid of parentheses

7x-6x+20-12=0

We add all the numbers together, and all the variables

x+8=0

We move all terms containing x to the left, all other terms to the right

x=-8

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