6x-13+2=6(3x-4)+6

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Solution for 6x-13+2=6(3x-4)+6 equation: 



6x-13+2=6(3x-4)+6

We move all terms to the left:

6x-13+2-(6(3x-4)+6)=0

We add all the numbers together, and all the variables

6x-(6(3x-4)+6)-11=0



We calculate terms in parentheses: -(6(3x-4)+6), so:

6(3x-4)+6

We multiply parentheses

18x-24+6

We add all the numbers together, and all the variables

18x-18

Back to the equation:

-(18x-18)



We get rid of parentheses

6x-18x+18-11=0

We add all the numbers together, and all the variables

-12x+7=0

We move all terms containing x to the left, all other terms to the right

-12x=-7

x=-7/-12

x=7/12

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