6x-2(2x+5)=-(x-2)+10

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Solution for 6x-2(2x+5)=-(x-2)+10 equation: 



6x-2(2x+5)=-(x-2)+10

We move all terms to the left:

6x-2(2x+5)-(-(x-2)+10)=0

We multiply parentheses

6x-4x-(-(x-2)+10)-10=0



We calculate terms in parentheses: -(-(x-2)+10), so:

-(x-2)+10

We get rid of parentheses

-x+2+10

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

-(-1x+12)



We add all the numbers together, and all the variables

2x-(-1x+12)-10=0

We get rid of parentheses

2x+1x-12-10=0

We add all the numbers together, and all the variables

3x-22=0

We move all terms containing x to the left, all other terms to the right

3x=22

x=22/3

x=7+1/3

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