6x-2(3-2x)=3(x-4)-22

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Solution for 6x-2(3-2x)=3(x-4)-22 equation: 



6x-2(3-2x)=3(x-4)-22

We move all terms to the left:

6x-2(3-2x)-(3(x-4)-22)=0

We add all the numbers together, and all the variables

6x-2(-2x+3)-(3(x-4)-22)=0

We multiply parentheses

6x+4x-(3(x-4)-22)-6=0



We calculate terms in parentheses: -(3(x-4)-22), so:

3(x-4)-22

We multiply parentheses

3x-12-22

We add all the numbers together, and all the variables

3x-34

Back to the equation:

-(3x-34)



We add all the numbers together, and all the variables

10x-(3x-34)-6=0

We get rid of parentheses

10x-3x+34-6=0

We add all the numbers together, and all the variables

7x+28=0

We move all terms containing x to the left, all other terms to the right

7x=-28

x=-28/7

x=-4

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