6x-2(3x+1)+3=4x-3-4(x-1)

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Solution for 6x-2(3x+1)+3=4x-3-4(x-1) equation: 



6x-2(3x+1)+3=4x-3-4(x-1)

We move all terms to the left:

6x-2(3x+1)+3-(4x-3-4(x-1))=0

We multiply parentheses

6x-6x-(4x-3-4(x-1))-2+3=0



We calculate terms in parentheses: -(4x-3-4(x-1)), so:

4x-3-4(x-1)

determiningTheFunctionDomain
4x-4(x-1)-3

We multiply parentheses

4x-4x+4-3

We add all the numbers together, and all the variables

1

Back to the equation:

-(1)



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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