6x-2(3x-30)=5(x-12)

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Solution for 6x-2(3x-30)=5(x-12) equation: 



6x-2(3x-30)=5(x-12)

We move all terms to the left:

6x-2(3x-30)-(5(x-12))=0

We multiply parentheses

6x-6x-(5(x-12))+60=0



We calculate terms in parentheses: -(5(x-12)), so:

5(x-12)

We multiply parentheses

5x-60

Back to the equation:

-(5x-60)



We add all the numbers together, and all the variables

-(5x-60)+60=0

We get rid of parentheses

-5x+60+60=0

We add all the numbers together, and all the variables

-5x+120=0

We move all terms containing x to the left, all other terms to the right

-5x=-120

x=-120/-5

x=+24

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