6x-2(4-3x)=5(x-3)-7

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Solution for 6x-2(4-3x)=5(x-3)-7 equation: 



6x-2(4-3x)=5(x-3)-7

We move all terms to the left:

6x-2(4-3x)-(5(x-3)-7)=0

We add all the numbers together, and all the variables

6x-2(-3x+4)-(5(x-3)-7)=0

We multiply parentheses

6x+6x-(5(x-3)-7)-8=0



We calculate terms in parentheses: -(5(x-3)-7), so:

5(x-3)-7

We multiply parentheses

5x-15-7

We add all the numbers together, and all the variables

5x-22

Back to the equation:

-(5x-22)



We add all the numbers together, and all the variables

12x-(5x-22)-8=0

We get rid of parentheses

12x-5x+22-8=0

We add all the numbers together, and all the variables

7x+14=0

We move all terms containing x to the left, all other terms to the right

7x=-14

x=-14/7

x=-2

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