6x-2(x+2)=2-3(x-3)

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Solution for 6x-2(x+2)=2-3(x-3) equation: 



6x-2(x+2)=2-3(x-3)

We move all terms to the left:

6x-2(x+2)-(2-3(x-3))=0

We multiply parentheses

6x-2x-(2-3(x-3))-4=0



We calculate terms in parentheses: -(2-3(x-3)), so:

2-3(x-3)

determiningTheFunctionDomain
-3(x-3)+2

We multiply parentheses

-3x+9+2

We add all the numbers together, and all the variables

-3x+11

Back to the equation:

-(-3x+11)



We add all the numbers together, and all the variables

4x-(-3x+11)-4=0

We get rid of parentheses

4x+3x-11-4=0

We add all the numbers together, and all the variables

7x-15=0

We move all terms containing x to the left, all other terms to the right

7x=15

x=15/7

x=2+1/7

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