6x-2(x+2)=3(x+2)+x-5

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Solution for 6x-2(x+2)=3(x+2)+x-5 equation: 



6x-2(x+2)=3(x+2)+x-5

We move all terms to the left:

6x-2(x+2)-(3(x+2)+x-5)=0

We multiply parentheses

6x-2x-(3(x+2)+x-5)-4=0



We calculate terms in parentheses: -(3(x+2)+x-5), so:

3(x+2)+x-5

We add all the numbers together, and all the variables

x+3(x+2)-5

We multiply parentheses

x+3x+6-5

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

4x-(4x+1)-4=0

We get rid of parentheses

4x-4x-1-4=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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