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6x-2(x-1)+1=3+4(3+2x)
We move all terms to the left:
6x-2(x-1)+1-(3+4(3+2x))=0
We add all the numbers together, and all the variables
6x-2(x-1)-(3+4(2x+3))+1=0
We multiply parentheses
6x-2x-(3+4(2x+3))+2+1=0
We calculate terms in parentheses: -(3+4(2x+3)), so:We add all the numbers together, and all the variables
3+4(2x+3)
determiningTheFunctionDomain 4(2x+3)+3
We multiply parentheses
8x+12+3
We add all the numbers together, and all the variables
8x+15
Back to the equation:
-(8x+15)
4x-(8x+15)+3=0
We get rid of parentheses
4x-8x-15+3=0
We add all the numbers together, and all the variables
-4x-12=0
We move all terms containing x to the left, all other terms to the right
-4x=12
x=12/-4
x=-3
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