6x-2(x-2)=4(x+1)+3

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Solution for 6x-2(x-2)=4(x+1)+3 equation: 



6x-2(x-2)=4(x+1)+3

We move all terms to the left:

6x-2(x-2)-(4(x+1)+3)=0

We multiply parentheses

6x-2x-(4(x+1)+3)+4=0



We calculate terms in parentheses: -(4(x+1)+3), so:

4(x+1)+3

We multiply parentheses

4x+4+3

We add all the numbers together, and all the variables

4x+7

Back to the equation:

-(4x+7)



We add all the numbers together, and all the variables

4x-(4x+7)+4=0

We get rid of parentheses

4x-4x-7+4=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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