6x-2(x-3)=(4x+1)+4

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Solution for 6x-2(x-3)=(4x+1)+4 equation: 



6x-2(x-3)=(4x+1)+4

We move all terms to the left:

6x-2(x-3)-((4x+1)+4)=0

We multiply parentheses

6x-2x-((4x+1)+4)+6=0



We calculate terms in parentheses: -((4x+1)+4), so:

(4x+1)+4

We get rid of parentheses

4x+1+4

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We add all the numbers together, and all the variables

4x-(4x+5)+6=0

We get rid of parentheses

4x-4x-5+6=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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