6x-2(x-3)=3(x+1)+1

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Solution for 6x-2(x-3)=3(x+1)+1 equation: 



6x-2(x-3)=3(x+1)+1

We move all terms to the left:

6x-2(x-3)-(3(x+1)+1)=0

We multiply parentheses

6x-2x-(3(x+1)+1)+6=0



We calculate terms in parentheses: -(3(x+1)+1), so:

3(x+1)+1

We multiply parentheses

3x+3+1

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

4x-(3x+4)+6=0

We get rid of parentheses

4x-3x-4+6=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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