6x-2(x-3)=4(x+1)+5

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Solution for 6x-2(x-3)=4(x+1)+5 equation: 



6x-2(x-3)=4(x+1)+5

We move all terms to the left:

6x-2(x-3)-(4(x+1)+5)=0

We multiply parentheses

6x-2x-(4(x+1)+5)+6=0



We calculate terms in parentheses: -(4(x+1)+5), so:

4(x+1)+5

We multiply parentheses

4x+4+5

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

4x-(4x+9)+6=0

We get rid of parentheses

4x-4x-9+6=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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