6x-2(x-6)=-4(x+1)+6

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Solution for 6x-2(x-6)=-4(x+1)+6 equation: 



6x-2(x-6)=-4(x+1)+6

We move all terms to the left:

6x-2(x-6)-(-4(x+1)+6)=0

We multiply parentheses

6x-2x-(-4(x+1)+6)+12=0



We calculate terms in parentheses: -(-4(x+1)+6), so:

-4(x+1)+6

We multiply parentheses

-4x-4+6

We add all the numbers together, and all the variables

-4x+2

Back to the equation:

-(-4x+2)



We add all the numbers together, and all the variables

4x-(-4x+2)+12=0

We get rid of parentheses

4x+4x-2+12=0

We add all the numbers together, and all the variables

8x+10=0

We move all terms containing x to the left, all other terms to the right

8x=-10

x=-10/8

x=-1+1/4

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