6x-2(x-7)=4(x+1)+4

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Solution for 6x-2(x-7)=4(x+1)+4 equation: 



6x-2(x-7)=4(x+1)+4

We move all terms to the left:

6x-2(x-7)-(4(x+1)+4)=0

We multiply parentheses

6x-2x-(4(x+1)+4)+14=0



We calculate terms in parentheses: -(4(x+1)+4), so:

4(x+1)+4

We multiply parentheses

4x+4+4

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

4x-(4x+8)+14=0

We get rid of parentheses

4x-4x-8+14=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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