6x-2(x-8)=4(x+1)+2

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Solution for 6x-2(x-8)=4(x+1)+2 equation: 


Simplifying
6x + -2(x + -8) = 4(x + 1) + 2

Reorder the terms:
6x + -2(-8 + x) = 4(x + 1) + 2
6x + (-8 * -2 + x * -2) = 4(x + 1) + 2
6x + (16 + -2x) = 4(x + 1) + 2

Reorder the terms:
16 + 6x + -2x = 4(x + 1) + 2

Combine like terms: 6x + -2x = 4x
16 + 4x = 4(x + 1) + 2

Reorder the terms:
16 + 4x = 4(1 + x) + 2
16 + 4x = (1 * 4 + x * 4) + 2
16 + 4x = (4 + 4x) + 2

Reorder the terms:
16 + 4x = 4 + 2 + 4x

Combine like terms: 4 + 2 = 6
16 + 4x = 6 + 4x

Add '-4x' to each side of the equation.
16 + 4x + -4x = 6 + 4x + -4x

Combine like terms: 4x + -4x = 0
16 + 0 = 6 + 4x + -4x
16 = 6 + 4x + -4x

Combine like terms: 4x + -4x = 0
16 = 6 + 0
16 = 6

Solving
16 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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