6x-2+(3(x-1)+4x+2)=10x

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Solution for 6x-2+(3(x-1)+4x+2)=10x equation: 



6x-2+(3(x-1)+4x+2)=10x

We move all terms to the left:

6x-2+(3(x-1)+4x+2)-(10x)=0

We add all the numbers together, and all the variables

-4x+(3(x-1)+4x+2)-2=0



We calculate terms in parentheses: +(3(x-1)+4x+2), so:

3(x-1)+4x+2

We add all the numbers together, and all the variables

4x+3(x-1)+2

We multiply parentheses

4x+3x-3+2

We add all the numbers together, and all the variables

7x-1

Back to the equation:

+(7x-1)



We get rid of parentheses

-4x+7x-1-2=0

We add all the numbers together, and all the variables

3x-3=0

We move all terms containing x to the left, all other terms to the right

3x=3

x=3/3

x=1

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