6x-23=3x+1+40

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Solution for 6x-23=3x+1+40 equation: 



6x-23=3x+1+40

We move all terms to the left:

6x-23-(3x+1+40)=0

We add all the numbers together, and all the variables

6x-(3x+41)-23=0

We get rid of parentheses

6x-3x-41-23=0

We add all the numbers together, and all the variables

3x-64=0

We move all terms containing x to the left, all other terms to the right

3x=64

x=64/3

x=21+1/3

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