6x-2=(1x+10)+(4x+1)

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Solution for 6x-2=(1x+10)+(4x+1) equation: 



6x-2=(1x+10)+(4x+1)

We move all terms to the left:

6x-2-((1x+10)+(4x+1))=0

We add all the numbers together, and all the variables

6x-((x+10)+(4x+1))-2=0



We calculate terms in parentheses: -((x+10)+(4x+1)), so:

(x+10)+(4x+1)

We get rid of parentheses

x+4x+10+1

We add all the numbers together, and all the variables

5x+11

Back to the equation:

-(5x+11)



We get rid of parentheses

6x-5x-11-2=0

We add all the numbers together, and all the variables

x-13=0

We move all terms containing x to the left, all other terms to the right

x=13

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