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6x-2=-2(1/2-3x)
We move all terms to the left:
6x-2-(-2(1/2-3x))=0
Domain of the equation: 2-3x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-3x))!=-2
x!=-2/1
x!=-2
x∈R
6x-(-2(-3x+1/2))-2=0
We multiply all the terms by the denominator
6x*2))-(-2(-3x+1-2*2))=0
We add all the numbers together, and all the variables
6x*2))-(-2(-3x-3))=0
We add all the numbers together, and all the variables
-3x+6x*2))-(-2(=0
Wy multiply elements
12x^2-3x=0
a = 12; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·12·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*12}=\frac{6}{24} =1/4 $
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