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6x-2=4(2x-3)-2(x+5)
We move all terms to the left:
6x-2-(4(2x-3)-2(x+5))=0
We calculate terms in parentheses: -(4(2x-3)-2(x+5)), so:We get rid of parentheses
4(2x-3)-2(x+5)
We multiply parentheses
8x-2x-12-10
We add all the numbers together, and all the variables
6x-22
Back to the equation:
-(6x-22)
6x-6x+22-2=0
We add all the numbers together, and all the variables
20!=0
There is no solution for this equation
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