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6x-2x(x-5)-10=22
We move all terms to the left:
6x-2x(x-5)-10-(22)=0
We add all the numbers together, and all the variables
6x-2x(x-5)-32=0
We multiply parentheses
-2x^2+6x+10x-32=0
We add all the numbers together, and all the variables
-2x^2+16x-32=0
a = -2; b = 16; c = -32;
Δ = b2-4ac
Δ = 162-4·(-2)·(-32)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-16}{-4}=+4$
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