6x-3(2+x2)=-6

Solution for 6x-3(2+x2)=-6 equation:

6x-3(2+x2)=-6

We move all terms to the left:

6x-3(2+x2)-(-6)=0

We add all the numbers together, and all the variables

-3(+x^2+2)+6x-(-6)=0

We add all the numbers together, and all the variables

-3(+x^2+2)+6x+6=0

We multiply parentheses

-3x^2+6x-6+6=0

We add all the numbers together, and all the variables

-3x^2+6x=0

a = -3; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-3)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-3}=\frac{-12}{-6}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-3}=\frac{0}{-6}
=0
$