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6x-3(2x-4)=3(x-1)
We move all terms to the left:
6x-3(2x-4)-(3(x-1))=0
We multiply parentheses
6x-6x-(3(x-1))+12=0
We calculate terms in parentheses: -(3(x-1)), so:We add all the numbers together, and all the variables
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
-(3x-3)+12=0
We get rid of parentheses
-3x+3+12=0
We add all the numbers together, and all the variables
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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