6x-3(3x+2)=3(x-2)-90

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Solution for 6x-3(3x+2)=3(x-2)-90 equation: 



6x-3(3x+2)=3(x-2)-90

We move all terms to the left:

6x-3(3x+2)-(3(x-2)-90)=0

We multiply parentheses

6x-9x-(3(x-2)-90)-6=0



We calculate terms in parentheses: -(3(x-2)-90), so:

3(x-2)-90

We multiply parentheses

3x-6-90

We add all the numbers together, and all the variables

3x-96

Back to the equation:

-(3x-96)



We add all the numbers together, and all the variables

-3x-(3x-96)-6=0

We get rid of parentheses

-3x-3x+96-6=0

We add all the numbers together, and all the variables

-6x+90=0

We move all terms containing x to the left, all other terms to the right

-6x=-90

x=-90/-6

x=+15

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