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6x-3(3x+9)=8-(2-x)
We move all terms to the left:
6x-3(3x+9)-(8-(2-x))=0
We add all the numbers together, and all the variables
6x-3(3x+9)-(8-(-1x+2))=0
We multiply parentheses
6x-9x-(8-(-1x+2))-27=0
We calculate terms in parentheses: -(8-(-1x+2)), so:We add all the numbers together, and all the variables
8-(-1x+2)
determiningTheFunctionDomain -(-1x+2)+8
We get rid of parentheses
1x-2+8
We add all the numbers together, and all the variables
x+6
Back to the equation:
-(x+6)
-3x-(x+6)-27=0
We get rid of parentheses
-3x-x-6-27=0
We add all the numbers together, and all the variables
-4x-33=0
We move all terms containing x to the left, all other terms to the right
-4x=33
x=33/-4
x=-8+1/4
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