6x-3(3x-4)=2(x-7)-4

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Solution for 6x-3(3x-4)=2(x-7)-4 equation:



6x-3(3x-4)=2(x-7)-4
We move all terms to the left:
6x-3(3x-4)-(2(x-7)-4)=0
We multiply parentheses
6x-9x-(2(x-7)-4)+12=0
We calculate terms in parentheses: -(2(x-7)-4), so:
2(x-7)-4
We multiply parentheses
2x-14-4
We add all the numbers together, and all the variables
2x-18
Back to the equation:
-(2x-18)
We add all the numbers together, and all the variables
-3x-(2x-18)+12=0
We get rid of parentheses
-3x-2x+18+12=0
We add all the numbers together, and all the variables
-5x+30=0
We move all terms containing x to the left, all other terms to the right
-5x=-30
x=-30/-5
x=+6

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