6x-3(3x-4)=2(x-7)-4

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Solution for 6x-3(3x-4)=2(x-7)-4 equation: 



6x-3(3x-4)=2(x-7)-4

We move all terms to the left:

6x-3(3x-4)-(2(x-7)-4)=0

We multiply parentheses

6x-9x-(2(x-7)-4)+12=0



We calculate terms in parentheses: -(2(x-7)-4), so:

2(x-7)-4

We multiply parentheses

2x-14-4

We add all the numbers together, and all the variables

2x-18

Back to the equation:

-(2x-18)



We add all the numbers together, and all the variables

-3x-(2x-18)+12=0

We get rid of parentheses

-3x-2x+18+12=0

We add all the numbers together, and all the variables

-5x+30=0

We move all terms containing x to the left, all other terms to the right

-5x=-30

x=-30/-5

x=+6

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