6x-3(4-2x)+5=23-2x-3(2+5x)

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Solution for 6x-3(4-2x)+5=23-2x-3(2+5x) equation: 



6x-3(4-2x)+5=23-2x-3(2+5x)

We move all terms to the left:

6x-3(4-2x)+5-(23-2x-3(2+5x))=0

We add all the numbers together, and all the variables

6x-3(-2x+4)-(23-2x-3(5x+2))+5=0

We multiply parentheses

6x+6x-(23-2x-3(5x+2))-12+5=0



We calculate terms in parentheses: -(23-2x-3(5x+2)), so:

23-2x-3(5x+2)

determiningTheFunctionDomain
-2x-3(5x+2)+23

We multiply parentheses

-2x-15x-6+23

We add all the numbers together, and all the variables

-17x+17

Back to the equation:

-(-17x+17)



We add all the numbers together, and all the variables

12x-(-17x+17)-7=0

We get rid of parentheses

12x+17x-17-7=0

We add all the numbers together, and all the variables

29x-24=0

We move all terms containing x to the left, all other terms to the right

29x=24

x=24/29

x=24/29

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