6x-3(5x+2)=4(1+x)

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Solution for 6x-3(5x+2)=4(1+x) equation: 



6x-3(5x+2)=4(1+x)

We move all terms to the left:

6x-3(5x+2)-(4(1+x))=0

We add all the numbers together, and all the variables

6x-3(5x+2)-(4(x+1))=0

We multiply parentheses

6x-15x-(4(x+1))-6=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

-9x-(4x+4)-6=0

We get rid of parentheses

-9x-4x-4-6=0

We add all the numbers together, and all the variables

-13x-10=0

We move all terms containing x to the left, all other terms to the right

-13x=10

x=10/-13

x=-10/13

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