6x-3(x+2)=2(x+5)

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Solution for 6x-3(x+2)=2(x+5) equation: 



6x-3(x+2)=2(x+5)

We move all terms to the left:

6x-3(x+2)-(2(x+5))=0

We multiply parentheses

6x-3x-(2(x+5))-6=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

3x-(2x+10)-6=0

We get rid of parentheses

3x-2x-10-6=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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