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6x-3(x-3)=2(x+6)-8
We move all terms to the left:
6x-3(x-3)-(2(x+6)-8)=0
We multiply parentheses
6x-3x-(2(x+6)-8)+9=0
We calculate terms in parentheses: -(2(x+6)-8), so:We add all the numbers together, and all the variables
2(x+6)-8
We multiply parentheses
2x+12-8
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
3x-(2x+4)+9=0
We get rid of parentheses
3x-2x-4+9=0
We add all the numbers together, and all the variables
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5
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