6x-3(x-4)=27

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Solution for 6x-3(x-4)=27 equation: 



6x-3(x-4)=27

We move all terms to the left:

6x-3(x-4)-(27)=0

We multiply parentheses

6x-3x+12-27=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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