6x-3+4x=8x-2(x-2)

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Solution for 6x-3+4x=8x-2(x-2) equation: 



6x-3+4x=8x-2(x-2)

We move all terms to the left:

6x-3+4x-(8x-2(x-2))=0

We add all the numbers together, and all the variables

10x-(8x-2(x-2))-3=0



We calculate terms in parentheses: -(8x-2(x-2)), so:

8x-2(x-2)

We multiply parentheses

8x-2x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

10x-6x-4-3=0

We add all the numbers together, and all the variables

4x-7=0

We move all terms containing x to the left, all other terms to the right

4x=7

x=7/4

x=1+3/4

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