6x-35=(4x-20)+19

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Solution for 6x-35=(4x-20)+19 equation: 



6x-35=(4x-20)+19

We move all terms to the left:

6x-35-((4x-20)+19)=0



We calculate terms in parentheses: -((4x-20)+19), so:

(4x-20)+19

We get rid of parentheses

4x-20+19

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We get rid of parentheses

6x-4x+1-35=0

We add all the numbers together, and all the variables

2x-34=0

We move all terms containing x to the left, all other terms to the right

2x=34

x=34/2

x=17

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