6x-38=2(5x+1)

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Solution for 6x-38=2(5x+1) equation:



6x-38=2(5x+1)
We move all terms to the left:
6x-38-(2(5x+1))=0
We calculate terms in parentheses: -(2(5x+1)), so:
2(5x+1)
We multiply parentheses
10x+2
Back to the equation:
-(10x+2)
We get rid of parentheses
6x-10x-2-38=0
We add all the numbers together, and all the variables
-4x-40=0
We move all terms containing x to the left, all other terms to the right
-4x=40
x=40/-4
x=-10

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