6x-3=2(x+1)+4x-4

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Solution for 6x-3=2(x+1)+4x-4 equation: 



6x-3=2(x+1)+4x-4

We move all terms to the left:

6x-3-(2(x+1)+4x-4)=0



We calculate terms in parentheses: -(2(x+1)+4x-4), so:

2(x+1)+4x-4

We add all the numbers together, and all the variables

4x+2(x+1)-4

We multiply parentheses

4x+2x+2-4

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

6x-6x+2-3=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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