6x-4(2x+1)=2(x+6)-28

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Solution for 6x-4(2x+1)=2(x+6)-28 equation: 



6x-4(2x+1)=2(x+6)-28

We move all terms to the left:

6x-4(2x+1)-(2(x+6)-28)=0

We multiply parentheses

6x-8x-(2(x+6)-28)-4=0



We calculate terms in parentheses: -(2(x+6)-28), so:

2(x+6)-28

We multiply parentheses

2x+12-28

We add all the numbers together, and all the variables

2x-16

Back to the equation:

-(2x-16)



We add all the numbers together, and all the variables

-2x-(2x-16)-4=0

We get rid of parentheses

-2x-2x+16-4=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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