6x-4(2x-10)=40-2x

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Solution for 6x-4(2x-10)=40-2x equation:



6x-4(2x-10)=40-2x
We move all terms to the left:
6x-4(2x-10)-(40-2x)=0
We add all the numbers together, and all the variables
6x-4(2x-10)-(-2x+40)=0
We multiply parentheses
6x-8x-(-2x+40)+40=0
We get rid of parentheses
6x-8x+2x-40+40=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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