6x-4(2x-10)=40-2x

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Solution for 6x-4(2x-10)=40-2x equation: 



6x-4(2x-10)=40-2x

We move all terms to the left:

6x-4(2x-10)-(40-2x)=0

We add all the numbers together, and all the variables

6x-4(2x-10)-(-2x+40)=0

We multiply parentheses

6x-8x-(-2x+40)+40=0

We get rid of parentheses

6x-8x+2x-40+40=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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