6x-4(2x-3)+10=8

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Solution for 6x-4(2x-3)+10=8 equation: 



6x-4(2x-3)+10=8

We move all terms to the left:

6x-4(2x-3)+10-(8)=0

We add all the numbers together, and all the variables

6x-4(2x-3)+2=0

We multiply parentheses

6x-8x+12+2=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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