6x-4(2x-5)=5(2x-8)+12

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Solution for 6x-4(2x-5)=5(2x-8)+12 equation: 



6x-4(2x-5)=5(2x-8)+12

We move all terms to the left:

6x-4(2x-5)-(5(2x-8)+12)=0

We multiply parentheses

6x-8x-(5(2x-8)+12)+20=0



We calculate terms in parentheses: -(5(2x-8)+12), so:

5(2x-8)+12

We multiply parentheses

10x-40+12

We add all the numbers together, and all the variables

10x-28

Back to the equation:

-(10x-28)



We add all the numbers together, and all the variables

-2x-(10x-28)+20=0

We get rid of parentheses

-2x-10x+28+20=0

We add all the numbers together, and all the variables

-12x+48=0

We move all terms containing x to the left, all other terms to the right

-12x=-48

x=-48/-12

x=+4

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