6x-4(3-2x)=5(x-4)+10

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Solution for 6x-4(3-2x)=5(x-4)+10 equation: 



6x-4(3-2x)=5(x-4)+10

We move all terms to the left:

6x-4(3-2x)-(5(x-4)+10)=0

We add all the numbers together, and all the variables

6x-4(-2x+3)-(5(x-4)+10)=0

We multiply parentheses

6x+8x-(5(x-4)+10)-12=0



We calculate terms in parentheses: -(5(x-4)+10), so:

5(x-4)+10

We multiply parentheses

5x-20+10

We add all the numbers together, and all the variables

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

14x-(5x-10)-12=0

We get rid of parentheses

14x-5x+10-12=0

We add all the numbers together, and all the variables

9x-2=0

We move all terms containing x to the left, all other terms to the right

9x=2

x=2/9

x=2/9

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