6x-4(3-2x)=5(x-4)=-10

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Solution for 6x-4(3-2x)=5(x-4)=-10 equation: 



6x-4(3-2x)=5(x-4)=-10

We move all terms to the left:

6x-4(3-2x)-(5(x-4))=0

We add all the numbers together, and all the variables

6x-4(-2x+3)-(5(x-4))=0

We multiply parentheses

6x+8x-(5(x-4))-12=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We add all the numbers together, and all the variables

14x-(5x-20)-12=0

We get rid of parentheses

14x-5x+20-12=0

We add all the numbers together, and all the variables

9x+8=0

We move all terms containing x to the left, all other terms to the right

9x=-8

x=-8/9

x=-8/9

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