6x-4(x+1)=2(x-3)+2

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Solution for 6x-4(x+1)=2(x-3)+2 equation: 


Simplifying
6x + -4(x + 1) = 2(x + -3) + 2

Reorder the terms:
6x + -4(1 + x) = 2(x + -3) + 2
6x + (1 * -4 + x * -4) = 2(x + -3) + 2
6x + (-4 + -4x) = 2(x + -3) + 2

Reorder the terms:
-4 + 6x + -4x = 2(x + -3) + 2

Combine like terms: 6x + -4x = 2x
-4 + 2x = 2(x + -3) + 2

Reorder the terms:
-4 + 2x = 2(-3 + x) + 2
-4 + 2x = (-3 * 2 + x * 2) + 2
-4 + 2x = (-6 + 2x) + 2

Reorder the terms:
-4 + 2x = -6 + 2 + 2x

Combine like terms: -6 + 2 = -4
-4 + 2x = -4 + 2x

Add '4' to each side of the equation.
-4 + 4 + 2x = -4 + 4 + 2x

Combine like terms: -4 + 4 = 0
0 + 2x = -4 + 4 + 2x
2x = -4 + 4 + 2x

Combine like terms: -4 + 4 = 0
2x = 0 + 2x
2x = 2x

Add '-2x' to each side of the equation.
2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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