6x-4(x+1)=4(x-3)+8

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Solution for 6x-4(x+1)=4(x-3)+8 equation: 



6x-4(x+1)=4(x-3)+8

We move all terms to the left:

6x-4(x+1)-(4(x-3)+8)=0

We multiply parentheses

6x-4x-(4(x-3)+8)-4=0



We calculate terms in parentheses: -(4(x-3)+8), so:

4(x-3)+8

We multiply parentheses

4x-12+8

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

2x-(4x-4)-4=0

We get rid of parentheses

2x-4x+4-4=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0

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