6x-4+2x=8(x-1/2)

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Solution for 6x-4+2x=8(x-1/2) equation: 



6x-4+2x=8(x-1/2)

We move all terms to the left:

6x-4+2x-(8(x-1/2))=0

We add all the numbers together, and all the variables

6x+2x-(8(+x-1/2))-4=0

We add all the numbers together, and all the variables

8x-(8(+x-1/2))-4=0

We multiply all the terms by the denominator


8x*2))-(8(+x-1-4*2))=0

We add all the numbers together, and all the variables

8x*2))-(8(x-9))=0

We add all the numbers together, and all the variables

8x*2))-(8(x=0

Wy multiply elements

16x^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$

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