If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x-4=12/2x-4
We move all terms to the left:
6x-4-(12/2x-4)=0
Domain of the equation: 2x-4)!=0We get rid of parentheses
x∈R
6x-12/2x+4-4=0
We multiply all the terms by the denominator
6x*2x+4*2x-4*2x-12=0
Wy multiply elements
12x^2+8x-8x-12=0
We add all the numbers together, and all the variables
12x^2-12=0
a = 12; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·12·(-12)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*12}=\frac{-24}{24} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*12}=\frac{24}{24} =1 $
| 2x+x+4-12=-2 | | 6=5–(2x+3) | | 3a-2=4a=6 | | 3,7-5a=1,5a+0,7+3,5a | | 3(p+2)=1/4(12p+24) | | 5x-3x-11=1 | | 4p-23=8p-7 | | –x+1=2x+8 | | X²+95x+625=0 | | 20w−–9w−12w−16w=19 | | 5p+11=2p-1 | | -4(q+2q)=-4 | | 11d-9=3d+7 | | 10,1y+20-3,6y=0,8y+24-2,3y | | 37x-37=37 | | n=-14n-37 | | 11k-38=4k+32 | | 8x+3=4(2x-5) | | 11w+32=142 | | 3(f-1)=f+1 | | 9z-99=0 | | 6x+4=4(2x+1) | | 12y-24=84 | | 6p+13=61 | | 5x-2=2(2x+1)+x | | 5x4-125x2=0 | | 42x+12= | | 6x-17=3x+13 | | 5+3e,e=4 | | 5y+25=120 | | 3x-2=5(x-2) | | 2^3x^+5=64^x−7 |