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6x-4=8(2+1/4x)
We move all terms to the left:
6x-4-(8(2+1/4x))=0
Domain of the equation: 4x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6x-(8(1/4x+2))-4=0
We multiply all the terms by the denominator
6x*4x-4*4x+2))-(8(1+2))=0
We add all the numbers together, and all the variables
6x*4x-4*4x+2))-(83)=0
We add all the numbers together, and all the variables
6x*4x-4*4x=0
Wy multiply elements
24x^2-16x=0
a = 24; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·24·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*24}=\frac{32}{48} =2/3 $
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