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6x-4x(-2x+8)=10
We move all terms to the left:
6x-4x(-2x+8)-(10)=0
We multiply parentheses
8x^2+6x-32x-10=0
We add all the numbers together, and all the variables
8x^2-26x-10=0
a = 8; b = -26; c = -10;
Δ = b2-4ac
Δ = -262-4·8·(-10)
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{249}}{2*8}=\frac{26-2\sqrt{249}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{249}}{2*8}=\frac{26+2\sqrt{249}}{16} $
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